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RE: Re: Displays round the house


  • To: <ukha_d@xxxxxxx>
  • Subject: RE: Re: Displays round the house
  • From: "Martin" <ukha@xxxxxxx>
  • Date: Tue, 13 Aug 2002 07:49:55 +0100
  • Mailing-list: list ukha_d@xxxxxxx; contact ukha_d-owner@xxxxxxx
  • Reply-to: ukha_d@xxxxxxx

erm, 100Mbs actually uses 2 pairs the same as 10Mbs . It is the standard
now. I think you'll find the 4 pair version died a death.

-----Original Message-----
From: brougham Baker [mailto:me@xxxxxxx]
Sent: 13 August 2002 05:38
To: ukha_d@xxxxxxx Subject: Re: [ukha_d] Re: Displays round the house


Stuart Poulton <swp@xxxxxxx> wrote:
>> I advocate the use of CAT 5 becasue so many of us have these
>> networks in place. But how will we get power to drive these units to
>> the right spot?
>>
>> Is it fanciful to think we can power these displays over cat 5 as
>> well as control them?
>
> I'd need someone with more experience to clarify this, but ethernet
> uses only 2 pairs, making the remaining 2 pairs available.  I'm
> gussing required power would be under 1amp.
>
> Does anyone know what pairs Power over ethernet uses, what voltage,
> AC/DC, and what max current is ?

I'll start with the easy one as this whole project has me so excited :)

10Mbps (10Base-T) uses 2 pairs, 100Mbps (100Base-T) uses all 4 pairs but
i
doubt we will ever need 100Mbps for these control level coms. For the
sake
of the pedants out there there was a 100mbps (100Base-TX) protocol that
used
2 pairs but that died a death.

Power over Ethernet info can be found at
http://www.hyperlinktech.com/web/what_is_poe.html
<http://www.hyperlinktech.com/web/what_is_poe.html>  and a whole walk
through
to make you own at http://www.nycwireless.net/poe/
<http://www.nycwireless.net/poe/>  Basically 1,2,3,6 are
used for data and 4,5,7,8 for power, 2 conductors each for positive and
negative if single ended power is needed.

Cat5e is 24AWG copper with a resistance of <95ohms per km for some and
<25
for others (no idea why, anyone?). The reason i give the resistance's is
because i can't find any current ratings, although 0.2amp seems to stick
in
my head but that is for single conductors. Perhaps a physicist or EE can
tell us what current it will take for the two conductors. It seems it is
used at up to 48v DC, I don't ever want to try AC over them thanks, well
other than the data.

Bro






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