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Re: Digital photo frames comparison



I've been considering buying this one
Digi-Vue 8 Photo Frame Misco No.: 129656
http://www.misco.co.uk/productinformation/~129656~WW~/Digi-Vue%208%20%20Pho=
to%20Frame.htm

Looks to be best compromise between price, spec and quality.

Regards

Simon

----- Original Message -----=20
From: Paul Gordon=20
To: UKHA_D Group=20
Sent: 12 November 2006 10:04
Subject: [ukha_d] Digital photo frames comparison


Now I think we all know that the Philips digital frame that has been disc=
ussed here previously is pretty much (one of) the best around at the
moment=
. However the price of that one has been slowly creeping up, to the point
t=
hat the best price I know of at the moment is =A3130. There are new ones
ap=
pearing every day, at different price points, and with different
specificat=
ions... the quandary is, how to compare them...

SWMBO started off looking *just* at the display resolution (640x480, 720x=
480 and so on...), but then I thought, hang on, - that doesn't take into
ac=
count the screen size as well... - to truly do a qualitative comparison,
on=
e would need to work out the number of pixels in a given area - pixels per
=
square inch for example. - Anyone disagree?

First problem, - how to work out the area of any given display? - most pr=
oducts seem to give just one measurement, - this I presume is the diagonal
=
which is traditionally the measurement given for all kinds of screens. OK,
=
from that it is possible to work out the area using Pythagoras' theorem. -
=
Rats, I knew I should have paid attention during O'level maths! -
Although,=
I can honestly say that in the 25 years since I left school this is the FI=
RST time I've ever needed to use anything they were teaching in maths
class=
! - So I'll admit it, whilst I can rattle off the rule "In a right
angled t=
riangle the square of the hypotenuse is equal to the sum of the squares of
=
the other two sides." Yadda-yadda... - how in the heck do I use that
to ded=
uce the area of a 5.7 inch display?

Any mathematicians care to help me out?

Cheers

Paul G.

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=20=20=20

[Non-text portions of this message have been removed]



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