Re: Capacitor Selection

["Andrew Kilgore" <amkilgore@xxxxxxx>]

Hi,

I think I know the equation you're talking about: Q = CV.
As far as I remember, Q is the charge is Columbs, C is the capacitance in
Farads and V is the voltage (in Volts) across the plates.

Not sure if this helps at all in this instance.

Thanks,
Andy.

----- Original Message -----
From: "James Hoye" <james.hoye@xxxxxxx>
To: <ukha_d@xxxxxxx>
Sent: Monday, August 04, 2003 9:18 AM
Subject: RE: [ukha_d] Capacitor Selection


> > Just had a thought, could the "CV" be capacitance times
voltage ?
>
> C in capacitor terms relates to Coulombs, the unit of charge.
>
> /me tries and fails to remember any more A level physics...
>
> James H
>
>
> ** UKHA2004 BE THERE! ** - start planning now.
>
> http://www.automatedhome.co.uk
> Post message: ukha_d@xxxxxxx
> Subscribe:  ukha_d-subscribe@xxxxxxx
> Unsubscribe:  ukha_d-unsubscribe@xxxxxxx
> List owner:  ukha_d-owner@xxxxxxx
>
> Your use of Yahoo! Groups is subject to http://docs.yahoo.com/info/terms/
>
>