> Doing it this way should be safe for the LED and avoid the
> maths side of things. I don't know the formulas off the top
> of my head so cannot help with that at the moment.
>
The maths is like this, use ohms law
V=IR or R=V/I
So a 30ma current with 5v
Is R= 5/0.03 = 166R
Actualy you will find two items If max and If Typ, wich is usualy much
smaller
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