Re: {Spam?} RE: [OT] Excel/maths question

["Mark Harrison \(Yahoo!\)" <mph@xxxxxxxxxxxxxxx>]

OK, boys and girls....

For your next question:

I want to find the Radius R, of a sphere with volume X (m^3)

How do I do that :-)

M.



----- Original Message -----
From: "White, Peter" <peter.white@xxxxxxx>
To: <ukha_d@xxxxxxx>
Sent: Tuesday, March 23, 2004 12:04 PM
Subject: RE: {Spam?} RE: [ukha_d] [OT] Excel/maths question


> Thanks guys, you're all pub geniuses.
>
> Pete
>
> -----Original Message-----
> From: Ward, David [mailto:DAvid.Ward@xxxxxxx]
> Sent: 23 March 2004 12:13
> To: 'ukha_d@xxxxxxx'
> Subject: {Spam?} RE: [ukha_d] [OT] Excel/maths question
>
>
> \o/  I got it right!
>
> /jumps around like a child - nods to office full of staring people
&
returns
> to seat quietly/
>
> Dave
>
> -----Original Message-----
> From: Ward, David [mailto:DAvid.Ward@xxxxxxx]
> Sent: 23 March 2004 12:06
> To: 'ukha_d@xxxxxxx'
> Subject: RE: [ukha_d] [OT] Excel/maths question
>
>
> SQRT()  should give you the squareroot
>
> Area of a circle is PI x Radius x Radius
>
> so in your example 424 = PI x Radius x Radius
>
> Radius = SQRT (424 / PI())
>
> so your diameter is 2 * (SQRT(424 /PI()))
>
>
> HTH
>
> Dave
>
> PS can someone check the maths ;-)
>
>
>
>
>
> -----Original Message-----
> From: White, Peter [mailto:peter.white@xxxxxxx]
> Sent: 23 March 2004 11:46
> To: 'ukha_d@xxxxxxx'
> Subject: [ukha_d] [OT] Excel/maths question
>
>
> It's been at east a month since I asked an Excel question ;-)
>
> This one should be easy for the maths guru's out there, if I've got a
square
> area of 424km (for example), how do I work out the dimensions of the
square,
> or, even better, the diameter of a circle based on 424km/sq.
>
> Thanks
>
> ______________________________________________
> Pete White
>
>
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