RE: LED Fun Challenge

["Alex Monaghan" <ha@xxxxxxxxxxxxxx>]

What about a PIC (or other microcontroller) ?

Use 2 pins as inputs to be triggered by the PIR's and then simply sequence
up or down the remaining pins to turn on the LED's in the correct order ? I
guess you'll want to use the other PIR input as a trigger to initiate the
timer. You could also do some clever stuff such as starting an alternative
sequence of lights in the event of a 2nd trigger being activated whilst the
lights are still on :-)

> -----Original Message-----
> From: Rob Mouser [mailto:groups@xxxxxxx]
> Sent: Tuesday, August 03, 2004 6:34 PM
> To: ukha_d@xxxxxxx
> Subject: [ukha_d] LED Fun Challenge
>
> A friend of mine has just moved into a new (very posh) pad. He has an
oak
> and steel spiral staircase and wants to add some discreet LED lighting
to
> it. But of course just on/off wont do! He wants to have pir activation
> from
> the top and the bottom AND when it is activated he wants the LED
lights to
> come on in sequence one step at a time (Fairly fast.) and then all
remain
> lit for a set period of minutes. But it doesn't stop there! He wants
the
> sequence to start at the top if activating the upstairs pir and start
from
> the bottom if activating from the bottom. Oh my life!
>
> I went kinda grey when he suggested all this but he is fairly adamant
he
> wants to do it. I reckon c-bus might do it but that would involve,
pir's,
> 2
> x 12 ch relays (for each step.), transformers for each LED and a great
> deal
> of thought. He doesn't have any c-bus at present (Standard lighting.)
so
> that seems overkill. Color Kinetics with DMX control is also an
option,
> again flippin expensive for a staircase.
>
> Surely a relay board can be made that is programmed to sequence 12v as
> required? Perhaps with one single power input?
>
> As I said hes adamant that he wants this, can anyone come up with an
idea?
> Commercial solution? Anyone want a one of job to build the circuit?
>
> Personally I think he's barmy but hey each to their own!
>
>
>
> Rob
>
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