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RE: OT VB question
- To: <ukha_d@xxxxxxx>
- Subject: RE: OT VB question
- From: "Keith Doxey" <ukha@xxxxxxx>
- Date: Fri, 1 Jun 2001 10:53:01 +0100
- Delivered-to: rich@xxxxxxx
- Delivered-to: mailing list ukha_d@xxxxxxx
- Mailing-list: list ukha_d@xxxxxxx; contact
ukha_d-owner@xxxxxxx
- Reply-to: ukha_d@xxxxxxx
If you just want to remove or replace a particular character which is what
I
guess you are trying to do with a varaiable called "StripStr" why
not use
the Replace function.
Replace(expression, find, replacewith[, start[, count[, compare]]])
MyString = Replace("XXpXXPXXp", "p", "Y") '
A binary comparison starting at
the beginning
' of the string. Returns "XXYXXPXXY".
MyString = Replace("XXpXXPXXp", "p", "Y",1)'
A textual comparison starting
at position 3.
' Returns "YXXYXXY". 3, -1, 1)
Keith
----------------------------------------------------------------------------
----
> -----Original Message-----
> From: Dr John Tankard [mailto:john@xxxxxxx]
> Sent: 01 June 2001 10:45
> To: ukha_d@xxxxxxx
> Subject: [ukha_d] OT VB question
>
>
> Sorry for the OT question
>
> I am having to sort a problem in VB for a customer which I have never
used
> before.
>
> What is the escape chr when you wish to quote a quote ie.
>
> While InStr(StripStr,""") >0
> ....
>
>
> What do i need in front of the second quote ?
>
> Thanks in advance
>
> John
>
>
>
>
>
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