RE: Silent Phones

["Keith Doxey" <keith.doxey@xxxxxxx>]

There is one other way of stopping the ring but again that wont work with 2
wire phones only proper 3 wire phones.

If you short 3&5 together you will shunt all the bells and stop them
ringing. Unfortunately you will also have a severe effect on the audio
level
on the line whereas my diagram wont.

If you put a large enough capacitor across the line to shunt the ring it
would have a VERY low impedance at the frequencies where the 9600 baud dat
is and would kill that stone dead. It would also probably draw enough
current from the exchange whilst ringing that it would ring trip the call
just as if you had lifted and dropped the receiver.

Keith

> -----Original Message-----
> From: Nigel Orr [mailto:nigel@xxxxxxx]
> Sent: 12 October 2000 10:45
> To: ukha_d@xxxxxxx
> Subject: RE: [ukha_d] Silent Phones
>
>
> At 10:22 12/10/00 +0100, you wrote:
> >There isnt an easy way round it :-(
>
> There isn't, is there :-(
>
> I presume, as you know more about these things than I, that my idea of
> shunting the ring signal only but still passing CLID wouldn't be
> achievable?  I thought they might be far enough apart in
> frequency that you
> could reduce the ring signal on 2&5 enough with a simple filter to
stop
> phones ringing, without blocking the CLID data?
>
> What's the detail of the ring signal- is it 90V rms @16.3 Hz?  What's
the
> CLID- 9600 baud data?  Just pondering...
>
> Nigel
>
>
>
>
>
>


-------------------------- eGroups Sponsor -------------------------~-~>
No bidding, no
guesswork.  Just
great fares at Hotwire.
http://click.egroups.com/1/9750/9/_/2065/_/971348223/
---------------------------------------------------------------------_->